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y=x^2-x(1) ;把區間[0,1]分成n等分(2) ;用第i個社區間的右端點的函數值的絕對值,作為第i個第i個小矩形的長. ; ; ; ; ; ;第i個小矩形的面積近似值為:S(i)≈[(i/n)^2-i/n]/n(…
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