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首先,函數y=(x-1)^3-1在(-∞,+∞)內具有任意階導數,所以曲線的拐點如果存在,其橫坐標一定是函數的二階導數為零的點. 其次,y''=6(x-1),令y''=0得x=1. x>1時,y''>0,x<1是,y''<0. x=1時,y=-1. 所以,曲線y=(x-1)^3-1的拐點是(1,-1)
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