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1]y=x²;-x³;的定義域為:R2]y'=2x-3x²;y''=2-6x解方程y''=0得x=1/3在(-∞,1/3)內,y''>0,∴(-∞,1/3)是曲線y=x²;-x³;的凹區間;同理,[1/3,+∞)是曲線y=x²;-x³;的凸區間.(1/3,2/27)曲…
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