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將(0,3)代入y=(a+2)x²;+a²;-1得3=a²;-1,a²;=4解得a=2或-2因為當a=-2時,y=(a+2)x²;+a²;-1=3,不滿足,舍去所以已知二次函數y=(a+2)x²;+a²;-1的頂點座標為(0,3),則a=_2__…
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