Contact us
Choose a category below so we can get back to you as quickly as possible.
如圖,延長CF交AB於H,∵AE是角平分線,CF⊥AE,∴CF=FH,AH=AC,∴BH=AB-AH=AB-AC=5-2=3,又∵AD是中線,∴DF是△BCH的中位線,∴DF=12BH=12×3=1.5.
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.