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延長CG交AB於D ∵∠C=90°,AC=6,BC=8 ∴AB=√(AC²;+BC²;)=√(36+64)=10 ∵G是△ABC的重心 ∴CD是AB邊上的中線,CG=2/3CD ∴CD=AB/2=5(直角三角形中線特性) ∴CG=2/3×5=10/3
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