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令f(x)=2x+x-2,由於f(0)=-2<0,f(1)=1>0,∴f(0)f(1)<0,根據函數零點的判定定理可得f(x)的零點所在的區間為(0,1),故方程2x+x-2=0的解所在的區間為(0,1),故選B.
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