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設:直線斜率為k則直線方程為:y-4=k(x+5)分別令x=0求y及y=0求x可得直線與y軸和x軸的交點座標為:(0,5k+4)、(-(5k+4)/k,0)因直線與兩坐標軸圍成三角形面積為5,故有:(1/2)·I(5k+4)·[-(5k+4)/k]I=5整理得:(5k+…
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