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因為sinxcosx=[(sinx+cosx)^2-1]/2所以設y=sinx+cosx因為x∈(π/2,3π/2)所以y∈[-√2,1)所以f(x)=sinx-sinxcosx+cosx可以變化為f(y)=y-(y^2-1)/2=-1/2(y-1)^2+1 y∈[-√2,1)你將f(y)大致畫出來,可以看出f…
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