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根據點到圓心的距離和半徑相比,距離大於半徑的時候,點在圓外. (x+1)^2+(y+2)^2=5+a由此得到圓心座標為(-1,-2),半徑為√(5+a),求出原點到圓心的距離為√[(-1)^2+(-2)^2]=√5,所以√5>√(5+a),解不等式得-5
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