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y=1+3x-x³; y'=3-3x²; =-3(x+1)(x-1)=0 x1=-1 x2=1 y''=-6x y''(-1)=6>0 所以 x=-1是極小值點 y''(1)=-6 所以 x=1處取極大值=y(1)=1+3-1=3
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