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y=f(lnx) 那麼 y'=f '(lnx)*(lnx)'=1/x *f '(lnx) 再繼續求導得到二階導數 y“= -1/x^2 *f '(lnx)+1/x *f”(lnx)*(lnx)' = -1/x^2 *f '(lnx)+1/x^2 *f“(lnx)
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