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設B(x,y)為線段中點,p(x1,y1) x=1/2(x1+12)y=1/2(y1+0) 得x1=2x-12 y1=2y 又x1^2+y1^2=16 所以(2x-12)^2+(2y)^2=16 即(x-6)^2+y^2=4
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