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x/(x-3)-2m+ 1=m/(x-3)原式應該是這樣的 所以首先就是m≠3然後化為x+(x-3)(-2m+1)=m (-2m+2)x+5m-3=0 得:m≠1 條件是m≠3且m≠1 應該就是這樣,不知對不對?
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