F(x)=[(3次根號下x^2)-(2次根號下x)]除以x(x>=0)求F(x)在X=0處的極限 F(x)=[(3次根號下x^2)-(2次根號下x)]除以x(x>=0)求F(x)在X=0處的極限

F(x)=[(3次根號下x^2)-(2次根號下x)]除以x(x>=0)求F(x)在X=0處的極限 F(x)=[(3次根號下x^2)-(2次根號下x)]除以x(x>=0)求F(x)在X=0處的極限

limF(X)=lim [√(x+1)-1] [√(x+1)+1][B]/{[^3√(x+1)-1][√(x+1)+1][B]}
=lim[x+1-1][B]/[1+x-1][[√(x+1)+1]=limB/A=3/2