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f(0)=0+0+c=0 所以c=0 f(x+1)=a(x+1)²;+b(x+1) =ax²;+(2a+b)x+(a+b) =f(x)+x+1 =ax²;+(b+1)x+1 所以 2a+b=b+1 a+b=1 所以a=b=1/2 f(x)=x²;/2+x/2
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