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∵點(1,0)在函數y=ln(3x-2)上∴函數的導數為f′(x)=33x−2,當x=1時,f′(1)=3,則切線的斜率k=f′(1)=3,∵直線過點(1,0)∴切線方程為y-0=3(x-1),即y=3x-3,故選:B.
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