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當x>0時,f(x)=x+lnx是增函數,又f(1/e)=1/e -10從而f(x)在(0,+∞)上有唯一的零點,且零點在(1/e,1)內.因為f(x)是奇函數,影像關於原點對稱,所以f(x)在(-∞,0)上也有唯一的零點.又f(x)是定義在R上的奇函數,所以f(0…
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