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∵an=nn2+156=1n+156n≤1439∵1n+156n≤1439當且僅當n=239時取等,又由n∈N+,故數列{an}的最大項可能為第12項或第13項又∵當n=12時,a12=12122+156=125又∵當n=13時,a13=13132+156=125故第12項或第13項均為最大…
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