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當式子Tn=1-b裡面的b為bn時, 當n=1時,∵b1=T1=1-b1,∴b1=1/2 當n≥2時,∵Tn=1-bn,∴Tn-1=1-bn-1, 兩式相减得:bn=b(n-1)-bn,即:bn=1/2b(n-1) 故{bn}為首項和公比均為1/2 的等比數列, ∴bn=(1/2)^n
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