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an =n^2+n = n(n+1) =(1/3)[n(n+1)(n+2)-(n-1)n(n+1)] Sn =(1/3){ summation(i:1->n)[i(i+1)(i+2)-(i-1)i(i+1)] } =(1/3)n(n+1)(n+2)
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