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Sn=2n²;+n-1① S(n-1)=2(n-1)²;+(n-1)-1=2n²;-3n② ①-②得出 a(n)=S(n)--S(n-1)n=4n -1 n大於等於2 又n=1時代入①得出a(1)=2 所以當n=1時,a(1)=2 當n大於1時,a(n)==4n -1
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