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(2n+1)²;-1 =(2n+1+1)(2n+1-1) =(2n+2)(2n) =4n(n+1) n和n+1中必有一個是偶數 所以n(n+1)是2的倍數 所以4n(n+1)是8的倍數 所以能被8整除
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