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由已知:能被2整除的數就是0,2,4,6,8,…,100,是公差為2的等差數列,設有n項,則100=0+(n-1)×2得n=51,所以在0,1,2,3,…,100這101個整數中,能被2整除的數有51個.同理:能被3整除的數就是0,3,6,9…
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