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設級數∑n(an-a(n-1))的前n項和為:σn 設級數∑an的前n項和為:Sn 則:σn=nan-S(n-1)-a0 S(n-1)=nan-σn-a0 limS(n-1)=lim(nan)-limσn-a0存在 ∴級數∑an收斂.
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