3*(1+2+3+4+.n)-n =3*(1+n)*n/2-n =(3n^2+n)/2 怎麼化簡到最後一步

3*(1+2+3+4+.n)-n =3*(1+n)*n/2-n =(3n^2+n)/2 怎麼化簡到最後一步

解由3*(1+2+3+4+.n)-n =3*(1+n)*n/2-n
=(3n+3n^2)/2-n
=(3n+3n^2)/2-2n/2
=(3n+3n^2-2n)/2
=(3n^2+n)/2