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證明:在AC上截取AE=AB, 因為,AD平分角BAC 所以∠BAD=∠EAD, 又AD為公共邊, 所以△BAD≌△EAD(SAS), 所以BD=ED,∠AED=∠B, 在△CDE中,∠AED=∠EDC+∠C 又∠B=2∠C 所以∠EDC=∠C 所以DE=EC, 所以AC=AE+EC=AB+DE=AB+BD
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