設Sn=1*4+2*7+.n(3n+1)則Sn=

設Sn=1*4+2*7+.n(3n+1)則Sn=

Sn=1*4+2*7+.n(3n+1)
=3*1²+1+3*2²+2+…+3*n²+n
=3*(1²+2²+…+n²)+(1+2+…+n)
=3*n*(n+1)*(2n+1)/6+n*(n+1)/2
=n*(n+1)²