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(1)令a=-2,b=0. 有f(-2)=f(-2)+f(0)-6, 所以f(0)=6 令a=2,b=-2. f(0)=f(2)+f(-2)-6, 所以f(2)=0. (2)設X1>X2, f(X1)=f(X1-X2)+f(X2)-6 f(X1)-f(X2)=f(X1-X2)-6
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