已知方程4x²；-7x-3=0的兩根為x1、x2，則2/X1+2/X2=，（X1-X2）的絕對值，x1²；+x2²；=？，已知方程4x²；-7x-3=0的兩根為x1、x2，則2/X1+2/X2=，（X1-X2）的絕對值，x1²；+x2²；=？，

x1+x2=7/4
x1x2=-3/4
2/x1+2/x2=2（x1+x2）/x1x2=-14/3
|x1-x2|=√[（x1+x2）²；-4x1x2]=√97/4
x1²；+x2²；=（x1+x2）²；-2x1x2=73/16