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tan(πx/2)=cot(π/2-πx/2)=1/tan(π/2-πx/2)等價於1/(π/2-πx/2) lim[x→1](1-x)tan(πx/2) =lim[x→1](1-x)/(π/2-πx/2) =2/π 希望可以幫到你,如果解决了問題,請點下麵的“選為滿意回答”按鈕.
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