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已知abc是非零有理數 ab>0,則a,b同號 a+b+c=0:若a,b>0,則c0,則c
∵|a+b|=a+b或-a-b, ∴a+b=a-b或-a-b=a-b, 解得b=0或a=0, ∴ab=0.
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