Natural number n is a complete square number after adding line 2, and it is also a complete square number after subtracting 1. It is proved that natural number n satisfies the condition 4n-n ^ 2-3 > 0

Natural number n is a complete square number after adding line 2, and it is also a complete square number after subtracting 1. It is proved that natural number n satisfies the condition 4n-n ^ 2-3 > 0

Let n + 2 be the complete square number, and let a ^ 2 be the complete square number, and let n-1 be B ^ 2, so a ^ 2-B ^ 2 = (a + b) * (a-b) = n + 2 - (n-1) = 3. Since a and B are both natural numbers, there is a + B = 3, A-B = 1, and the solution is a = 2, B = 1, and then n = 2. By substituting, we can see that 4n-n ^ 2-3 = 4 * 2-2 * 2-3 = 1 > 0