∫ (3 + (arc TaNx power of 10)) / (1 + (2 power of x)) DX, find its indefinite integral! Most important!

∫ (3 + (arc TaNx power of 10)) / (1 + (2 power of x)) DX, find its indefinite integral! Most important!

First take apart: ∫ [3 / (1 + x ^ 2)] DX + ∫ [10 ^ arctanx / (1 + x ^ 2)] DX
The first integral is very simple. The result is 3arctanx. Is that ok?!
In the second integral, we can get darctanx by rounding 1 / (1 + x ^ 2) into DX by using the method of rounding differentiation. In this way, the original integral can be changed into ∫ [10 ^ arctanx] darctanx, and the result is (1 / ln10) * 10 ^ arctanx
In conclusion, the result of the original integral is 3arctanx + (1 / ln10) * 10 ^ arctanx + C (C is any constant)