If sin (π 3-A) = 14, then cos (π 3 + 2a) is equal to______ .

If sin (π 3-A) = 14, then cos (π 3 + 2a) is equal to______ .

∵ sin (π 3 - α) = sin [π 2 - (π 6 + α)] = cos (π 6 + α) = 14, ∵ cos (π 3 + 2 α) = Cos2 (π 6 + α) = 2cos2 (π 6 + α) - 1 = 2 × (14) 2-1 = - 78