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log2(9^x-4)=log2(3^x-2)+log2(8) log2(3^2x-4)=log2(8×3^x-8×2) 3^2x-4=8×3^x-16 a=3^xを設定 a^2-4=8a-16 a^2-8a+12=0 a1=2,a2=6 3^x1=2,3^x2=6 x1=log(3)2 x2=log(3)6
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