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令√x=u,則x=u²,dx=o_unk2_unk1 原式=(1→+∞)2ue^(-u)du =-∫(1→+∞)2u de^(-u) =-2ue^(-u)+2(1→+∞)e^(-u)du =-2ue^(-u)-2e^(-u)|(1→+∞)(1→+∞) =2e^(-1)+2e^(-1) =4/e
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