If we know that the complex Z is small 1 = 3 minus I and Z is small 2 = 2I minus 1, then the imaginary part of I minus 4 minus 2 is equal to? 1

If we know that the complex Z is small 1 = 3 minus I and Z is small 2 = 2I minus 1, then the imaginary part of I minus 4 minus 2 is equal to? 1

You mean Z1 = 3-I, Z2 = 2i-1.i/z1-z2 pull out / 4? If it is, the result is as follows:
I / Z1 - Z2 / 4 = (I / 3-I) - (- 2i-1 / 4) = 16i + 3 / 20
Its imaginary part = 16 / 20 = 4 / 5
As shown in the figure
The pictures need to be checked. Don't worry
/4=(i/3-i) - (-2i-1 /4)=16i+3/20
Its imaginary part = 16 / 20 = 4 / 5
Given the complex number Z = 2i1 + I, then Z2 is equal to ()
A. 2iB. -2iC. -2-2iD. -2+2i
From z = 2i1 + I = 2I (1 − I) (1 + I) (1 − I) = 2 + 2I2 = 1 + I. So Z2 = (1 + I) 2 = 1 + 2I + I2 = 2I
Find all complex numbers Z satisfying the following two conditions: (1) Z + 10 / Z ∈ R and 1
Let z = a + bi
a. B is an integer
z+10/z=a+bi+(10a-10bi)/(a^2+b^2)∈R
∴ b=10b/(a^2+b^2)
So B = 0, or a ^ 2 + B ^ 2 = 10
1)b=0
There is 1
Is the students singular or plural
Here, the key word is "students". The is just a definite article modifying students, which can be ignored. So the students are plural
Plural, generic
If the complex Z satisfies (3-3i) z = 6I (I is an imaginary unit), then the imaginary part of Z is ()
A. 32B. 32C. 3D. -12
From (3-3i) z = 6I, we get z = 6i3-3i = 6I (3 + 3I) (3-3i) (3 + 3I) = - 18 + 63i12 = - 32 + 32i, so the imaginary part of Z is 32, so we choose: a
If the complex number 2 + I / 1-2i is expressed as a + bi, then a + B =?
(2+i)/(1-2i)=(2+i)i/[(1-2i)i]=(2+i)i/(i-2i²)=(2+i)i/(i+2)=i=a+bi,
a=0,b=1,a+b=1
One
One point eight
Rationalizing the denominator
Concrete analysis of specific problems~
1/5：2+i/1-2i~~~4-3i/5
Are there brackets at the back?
The original formula = 2 + I (1 + 2I) / [((1-2i) (1 + 2I)] = 2 - (I-2) / 5 = 7 / 5-I / 5
Multiply by 1 + 2I at the same time
(1+2i)(2+i)/(1-2i)(1+2i)=(2+3i-2)/（1+4）
a=0 b=3/5
3 / 5 (1 + 2I) (2 + I) / (1-2i) (1 + 2I) = the square of 2 + 5I + 2I / the square of 1-4i = I, so a = 0, B = 1, a + B = 1 according to your method, why do I work out this way.. Is there something wrong with me? Take a look for me. Thank you.. I just miscalculated. You... Unfold
Multiply by 1 + 2I at the same time
(1+2i)(2+i)/(1-2i)(1+2i)=(2+3i-2)/（1+4）
a=0 b=3/5
3 / 5 question: (1 + 2I) (2 + I) / (1-2i) (1 + 2I) = the square of 2 + 5I + 2I / the square of 1-4i = I, so a = 0, B = 1, a + B = 1 according to your method, why do I work out this way.. Is there something wrong with me? Take a look for me. Thank you..
Is the students of our class singular or plural?
Mary and June are both teachers.But _____ of them works in Shanghai.
A.neither B.none C.either
The students of our class is plural
Look at students
I wish you a happy study
complex
complex
Plural, of course. The combination depends on the preceding words
Yes
Plural, of course
Of course, it's plural. The center word of the noun phrase here is students, so it's plural
It's definitely plural
It's plural, determined by students
Let the complex Z satisfy 4Z + 2Z = 3 √ 3 + I, and find the modulus of complex Z
z=a+bi
4a+4bi+2a+2bi=6a+6bi
A = root 3 / 2 b = 1 / 6
Module = radical 3 / 2 ^ 2 + 1 / 6 ^ 2 = radical 7 / 3
How does the complex number 5 / 1 + I become a + bi,
In this case, the numerator and denominator are multiplied by the same number
Where I-I is multiplied by the denominator of the complex number
5/(1+i)=(5*(1-i))/((1+i)(1-i))
=(5-5i)/2
=5/2-5i/2
The numerator and denominator are multiplied by 1-i. just multiply the conjugate complex number of the denominator
If the numerator and denominator are multiplied by (1-I), the denominator can be simplified by the square difference formula!
5/(1+i)=5(1-i)/(1+i)(1-i)=(5-5i)/2=2.5-2.5i
Multiply by 1-I
What's the difference between one of + plural and the one of + plural?
English teacher, let me answer
One of + noun plural, as a whole as singular
The one of + is plural, especially "that" in it
Nonsense, the mood is different when being the subject, the following one emphasizes one of them more "that one", the predicate verbs are singular!!!
It's the same as the one on the first floor.
When one of + plural noun is the subject, the predicate is singular,
When the plural of the noun is the subject, the predicate verb is singular
When one of + plural noun is used as subject, the predicate is plural, focusing on plural noun words;
When the plural of the noun is used as the subject, the predicate is singular and the focus is on one
This part belongs to: subject predicate consistency topic, you can use subject predicate consistency to find relevant information online.
When one of + plural noun is the subject, the predicate is plural
When the one of + noun is plural as subject, the predicate verb is singular
There's something wrong with what you said. It should be as follows
In attributive clause: if the antecedent is modified by one of, the predicate verb of the clause is plural
If the only one of modification, the clause is simple
Others: one of + plural noun as subject, predicate single
The one of + noun plural subject or predicate simple