A and B are coprime numbers, and their greatest common factor is______ The least common multiple is______ .

A and B are coprime numbers, and their greatest common factor is______ The least common multiple is______ .

Because a and B are coprime numbers, their greatest common factor is 1 and their least common multiple is ab
A and B are coprime numbers, and their greatest common factor is______ The least common multiple is______ .
Because a and B are coprime numbers, their greatest common factor is 1 and their least common multiple is ab
The greatest common factor and the least common multiple
1. Find the greatest common factor of two numbers in each group
15 and 20 33 and 44 21 and 28 13 and 65 7 and 28 8 and 9
6 and 12 1 and 13 17 and 34 10 and 21 18 and 36 24 and 16 5 and 9
39 and 42
1、 Five two, eleven three, seven four, five five, seven
6、 17, 68, 19, 17, 10, 11, 18
12、 4 13, 1 14, 3
Wish you happy every day!
5 11 7 13 7 1 6 1 17 1 18 8 1 13
...(^-^)...
15 and 20 -- 5 33 and 44 -- 11 21 and 28 -- 7 13 and 65 -- 13 7 and 28 -- 7 8 and 9 -- 1 6 and 12 -- 6 1 and 13 -- 1 17 and 34 -- 17 10 and 21 -- 1 18 and 36 -- 18 24 and 16 -- 8 5 and 9 -- 1
39 and 42 -- 3
Remember to give points!
Given 2Z + | Z | = 2 + 4I, find the complex Z
2＋4i－2z=|z|
Because | Z | is a real number, the imaginary part of 2 + 4i-2z on the left side of the equation is 0, and it is obtained that:
The imaginary part of Z is 2
Let z = a + 2I, where a ∈ R
2＋4i－2(a＋2i)=|z|
(2－2a)=|z|
(2－2a)²=|z|²=a²＋4
4a²－8a＋4=4＋a²
3a²－8a=0
A = 0 or a = 8 / 3
Then:
Z = 2I or Z = (8 / 3) + 2I
Let z = a + bi
A and B are real numbers
Because | Z | is a real number
So the imaginary part on the left is 2B
So 2B = 4
B=2
So 2A + 4I + √ (A & # 178; + 4) = 2 + 4I
√(a²+4)=2-2a
a²+4=4-8a+4a²
3a²-8a=0
a=0,a=8/3
Z = 2I, z = 8 / 3 + 2I: it seems wrong to substitute a = 8 / 3 with 2A + √ (a ^ 2 + 4) = 2
Write the polar equation for the following conditions
1. Through the pole, the linear equation with the inclination angle of π / 6 is?
2. The linear equation passing through point a (2, π / 4) and perpendicular to the polar axis is?
3. The linear equation passing through point B (3, - π / 3) and parallel to the polar axis is?
4. The linear equation passing through point C (4,0) and the inclination angle is 3 π / 4 is?
5. The circle equation with a (2,0) as the center and 2 as the radius is?
6. The circular equation with C (5, π) as the center and passing through the pole is?
7. The circular equation with B (4, π / 2) as the center and 4 as the radius is?
8. The circular equation with D (radical 2, π / 4) as the center and 1 as the radius is?
1. θ = pi / 6, (ρ is a real number)
Or θ = pi / 6 or θ = 7pi / 6 (ρ > = 0)
2. ρ cos θ = radical 2
3. ρ sin θ = - 3 root sign 3 / 2
4. ρ cos (θ - pi / 4) = 2, radical 2
5、ρ=4cosθ
6、ρ=-10cosθ
7、ρ=8sinθ
8、ρ^2-2ρcosθ-2ρsinθ+1=0
Satisfy 4x + 2Z (there is a cross on Z) = 3 times root sign 3 + I to find the module of complex Z
Let z = x + I * y
Then 4x + 2Z = 4x + 2x-2y * I = 6x-2y * I = 3 * 3 ^ 0.5 + I
So 6x = 3 * 3 ^ 0.5 - 2Y = 1
So x = 3 ^ 0.5 / 2, y = - 0.5
Module of Z = (x ^ 2 + y ^ 2) ^ 0.5 = 1
In the plane rectangular coordinate system, given that point a (3,0), P is a moving point on the circle x2 + y2 = 1, and the bisector of ∠ AOP intersects point Pa at point Q, the polar coordinate equation of the trajectory of point q is obtained
Taking o as the pole and the positive half axis of X axis as the polar axis, the polar coordinate system is established. Let Q (ρ, θ), then p (1,2 θ). ∵ s △ OPQ + s △ OQA = s △ OAP, ∵ 12 × 1 × ρ sin θ + 12 × 3 ρ sin θ = 12 × 3 × 1 × sin 2 θ. It is reduced to ρ = 32cos θ
If the complex Z is on the circle | Z | = 2, then prove: | 1 / (Z ^ 4-4z ^ 2 + 3)|
Because Z ^ 4-4z ^ 2 + 3 = (Z ^ 2-1) (Z ^ 2-3),
And | Z ^ 2-1 | > = | Z ^ 2 | - 1 = 3, | Z ^ 2-3 | > = | Z ^ 2 | - 3 = 1,
So | Z ^ 4-4z ^ 2 + 3 | > = 3,
So | 1 / (Z ^ 4-4z ^ 2 + 3)|
The line passing through point (2, Pai / 3) and perpendicular to the polar axis is
That is, through the rectangular coordinate system (1, root 3), the straight line is x = 1, that is, ρ cos θ = 1
Given that the sum of the complex Z and the module of its conjugate complex is equal to 2 + I, find Z
Let z = a + IB, then its conjugate is a-ib, the conjugate module of Z is sqrt (a * a + b * b), and the sum of Z and its conjugate module is a + sqrt (a * a + b * b) + IB;
a+sqrt(a*a+b*b)=2；
b=1;
A = 3 / 4 is obtained;
So z = (3 / 4) + I
I wonder if that's what you mean