已知dy/dx=2xy^2求其通解求∫dx/y^2

dy/dx＝2xy^2
==> dy/y^2＝2x dx
==>∫dy/y^2＝∫2x dx
==>－1/y＝x^2 + C
==> 1/y^2＝x^4 + 2C*x^2 + C^2
==>∫dx/y^2＝∫（x^4 + 2C*x^2 + C^2）dx
==>∫dx/y^2＝x^5 / 5 + 2C*x^3 / 3 + C^2 * x + D
C、D為任意常數