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y=(-x^2+Cx)^(1/3),C為任意常數 解題步驟: 3xy^2dy=(y^3-x^2)dx, (3xy^2)*y'=y^3-x^2, 又[(y^3)/x]'=[(3xy^2)*y'-(y^3)]/(x^2)=-1, 知(y^3)/x=-x+C,C為任意常數, 即y=(-x^2+Cx)^(1/3),C為任意常數
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