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顯然MN的中垂線為x軸,C在MN的中垂線上,故C為直線2x-y-6=0與x軸的交點(3,0) CM = r =√[(0-3)²;+(-2-0)²;]=√13 圓C的方程:(x - 3)²;+ y²;= 13
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