Contact us
Choose a category below so we can get back to you as quickly as possible.
該命題可轉化為求一條平行於y=x+3的直線y=x+b與拋物線y^2=4x相切,求出切點,此時點P到直線y=x+3的距離最短 (畫圖更直觀)聯立方程y=x+b,y^2=4x 得,x^2+(2b-4)x+b^2=0 Δ =0 ,(2b-4)^2-4b^2=0 ,b=1所以,x=1 ,y=2 ...
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.