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f’(x)=x^2+2ax+1 △=4a^2-4=4(a+1)(a-1) ①當△≤0, 即-1≤a≤1, 有 f’(x)≥0, 所以f(x)在R上單增. ②當△>0 即a1, 若x-a+√(a^2-1) 則f’(x)>0,f(x)單增 若-a-√(a^2-1)
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