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y=log(a)x+1 值域是R log(a)x=y-1 x=a^(y-1) 所以反函數y=a^(x-1),x∈R y=log(a)(x+1) 值域是R x+1=a^y x=-1+a^y 所以反函數y=-1+a^x,x∈R
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