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1求出反函數x=(y-B)/A對應係數相等則A=1/A B=-B/A聯立A=1時B=0 A=-1時B可取全體實數 2同樣求出它的反函數對應係數相等Y(X-1)=AX+2 X=(2+Y)/(Y-A)則A=1
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