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證明:如圖,∵AE平分∠BAC交BC於E,∴∠1=∠3.∵DE‖AC,∴∠2=∠3,∴∠1=∠3,∴∠1=∠2,∴AD=DE.又∵DE‖AC,DF‖BC,∴四邊形DECF是平行四邊形,∴DE=FC,∴AD=FC.
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