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設F(x)=g(x)-f(x)=lnx+e^x x>0 F'=(1/x)+e^x>0 F(x)為單調增函數 x→0+ F(0+)→-∞0 存在x0∈(0,1)F(x0)=0即方程f(x)=g(x)有唯一實數根
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