已知點A(5,y),B(1,2),且丨向量AB丨=5,則y=

已知點A(5,y),B(1,2),且丨向量AB丨=5,則y=

AB=(1-5,2-y)=(-4,2-y)

丨向量AB丨=5,

√(-4)²;+(2-y)²;=5
16+4-4y+y²;=25
y²;-4y-5=0
(y+1)(y-5)=0
y=-1或y=5