Contact us
Choose a category below so we can get back to you as quickly as possible.
由a,b均為正數,所以(b/a^2 + a/b^2)*(1/b + 1/a)(由柯西不等式)>=[根號(b/a^2 * 1/b)+根號(a/b^2 * 1/a)]^2=(1/a + 1/b)^2不等式兩邊同時除以1/a + 1/b即知b/a^2 + a/b^2 >= 1/a +1/b等號當且僅當a=b時取得….
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.